d3839ede05
Sourcing a GDB script that runs foreground execution commands in
succession fails if the target can async:
Breakpoint 1, main () at ../../../src/gdb/testsuite/gdb.base/source-execution.c:36
36 func1 ();
(gdb) source ../../../src/gdb/testsuite/gdb.base/source-execution.gdb
../../../src/gdb/testsuite/gdb.base/source-execution.gdb:21: Error in sourced command file:
Cannot execute this command while the selected thread is running.
(gdb) FAIL: gdb.base/source-execution.exp: source source-execution.gdb
That is, after a foreground execution command, GDB moves on to the
following command immediately before waiting for the previous command
to complete.
https://sourceware.org/ml/gdb-patches/2011-09/msg00037.html (b4a14fd0
)
addressed this for command lists, Python's gdb.execute, etc., but
missed "source". Fixed now in the same way.
gdb/
2014-03-25 Pedro Alves <palves@redhat.com>
* cli/cli-script.c (script_from_file): Force the interpreter to
sync mode.
gdb/testsuite/
2014-03-25 Pedro Alves <palves@redhat.com>
Doug Evans <dje@google.com>
* gdb.base/source-execution.c: New file.
* gdb.base/source-execution.exp: New file.
* gdb.base/source-execution.gdb: New file.
41 lines
908 B
C
41 lines
908 B
C
/* This testcase is part of GDB, the GNU debugger.
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Copyright 2014 Free Software Foundation, Inc.
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This program is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <http://www.gnu.org/licenses/>. */
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static void
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func1 (void)
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{
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}
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static void
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func2 (void)
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{
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}
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static void
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func3 (void)
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{
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}
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int
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main (void)
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{
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func1 ();
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func2 ();
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func3 ();
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return 0;
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}
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