18920c4226
Consider the following type:
type Char_Enum_Type is ('A', 'B', 'C', 'D');
If the compiler generates a Char_Enum_Type typedef in the debugging
information, the debugger fails in the following case:
(gdb) p Char_Enum_Type'('B')
$1 = 66
For our type, the underlying value of 'B' is actually 1, not 66
(ASCII 'B'). We are failing this case because we were not handling
typedef to enum types before. This patch fixes this.
gdb/ChangeLog:
* ada-exp.y (convert_char_literal): Handle typedef types.
gdb/testsuite/ChangeLog:
* gdb.ada/char_enum: New testcase.
23 lines
887 B
Ada
23 lines
887 B
Ada
-- Copyright 2011 Free Software Foundation, Inc.
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--
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-- This program is free software; you can redistribute it and/or modify
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-- it under the terms of the GNU General Public License as published by
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-- the Free Software Foundation; either version 3 of the License, or
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-- (at your option) any later version.
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--
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-- This program is distributed in the hope that it will be useful,
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-- but WITHOUT ANY WARRANTY; without even the implied warranty of
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-- MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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-- GNU General Public License for more details.
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--
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-- You should have received a copy of the GNU General Public License
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-- along with this program. If not, see <http://www.gnu.org/licenses/>.
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with Pck; use Pck;
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procedure Foo is
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type Char_Enum_Type is ('A', 'B', 'C', 'D', 'E');
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Char : Char_Enum_Type := 'D';
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begin
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Do_Nothing (Char'Address); -- STOP
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end Foo;
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