/* disassemble sparc instructions for objdump Copyright (C) 1986, 1987, 1989 Free Software Foundation, Inc. This file is part of the binutils. The binutils are free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 1, or (at your option) any later version. The binutils are distributed in the hope that they will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with the binutils; see the file COPYING. If not, write to the Free Software Foundation, 675 Mass Ave, Cambridge, MA 02139, USA. */ /* $Id$ */ #include "bfd.h" #include "sysdep.h" #include #include "sparc-opcode.h" extern int fputs(); extern int print_address(); static char *reg_names[] = { "g0", "g1", "g2", "g3", "g4", "g5", "g6", "g7", "o0", "o1", "o2", "o3", "o4", "o5", "sp", "o7", "l0", "l1", "l2", "l3", "l4", "l5", "l6", "l7", "i0", "i1", "i2", "i3", "i4", "i5", "fp", "i7", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "f10", "f11", "f12", "f13", "f14", "f15", "f16", "f17", "f18", "f19", "f20", "f21", "f22", "f23", "f24", "f25", "f26", "f27", "f28", "f29", "f30", "f31", "y", "psr", "wim", "tbr", "pc", "npc", "fpsr", "cpsr" }; #define freg_names (®_names[4 * 8]) union sparc_insn { unsigned long int code; struct { unsigned int _OP:2; #define op ldst._OP unsigned int _RD:5; #define rd ldst._RD unsigned int op3:6; unsigned int _RS1:5; #define rs1 ldst._RS1 unsigned int i:1; unsigned int _ASI:8; #define asi ldst._ASI unsigned int _RS2:5; #define rs2 ldst._RS2 #define shcnt rs2 } ldst; struct { unsigned int _OP:2, _RD:5, op3:6, _RS1:5, i:1; unsigned int IMM13:13; #define imm13 IMM13.IMM13 } IMM13; struct { unsigned int _OP:2; unsigned int a:1; unsigned int cond:4; unsigned int op2:3; unsigned int DISP22:22; #define disp22 branch.DISP22 } branch; #ifndef NO_V9 struct { unsigned int _OP:2, _RD:5, op3:6, _RS1:5; unsigned int DISP14:14; #define disp14 DISP14.DISP14 } DISP14; struct { unsigned int _OP:2; unsigned int a:1; unsigned int cond:4; unsigned int op2:3; unsigned int p:1; unsigned int DISP21:21; #define disp21 branch2.DISP21 } branch2; #endif /* NO_V9 */ #define imm22 disp22 struct { unsigned int _OP:2; unsigned int _DISP30:30; #define disp30 call._DISP30 } call; }; /* Nonzero if INSN is the opcode for a delayed branch. */ static int is_delayed_branch (insn) union sparc_insn insn; { unsigned int i; for (i = 0; i < NUMOPCODES; ++i) { const struct sparc_opcode *opcode = &sparc_opcodes[i]; if ((opcode->match & insn.code) == opcode->match && (opcode->lose & insn.code) == 0 && (opcode->flags&F_DELAYED)) return 1; } return 0; } static int opcodes_sorted = 0; /* Print one instruction from MEMADDR on STREAM. */ int print_insn_sparc (memaddr, buffer, stream) bfd_vma memaddr; bfd_byte *buffer; FILE *stream; { union sparc_insn insn; register unsigned int i; if (!opcodes_sorted) { static int compare_opcodes (); qsort ((char *) sparc_opcodes, NUMOPCODES, sizeof (sparc_opcodes[0]), compare_opcodes); opcodes_sorted = 1; } memcpy(&insn,buffer, sizeof (insn)); for (i = 0; i < NUMOPCODES; ++i) { const struct sparc_opcode *opcode = &sparc_opcodes[i]; if ((opcode->match & insn.code) == opcode->match && (opcode->lose & insn.code) == 0) { /* Nonzero means that we have found an instruction which has the effect of adding or or'ing the imm13 field to rs1. */ int imm_added_to_rs1 = 0; /* Nonzero means that we have found a plus sign in the args field of the opcode table. */ int found_plus = 0; /* Do we have an 'or' instruction where rs1 is the same as rsd, and which has the i bit set? */ if (opcode->match == 0x80102000 && insn.rs1 == insn.rd) imm_added_to_rs1 = 1; if (index (opcode->args, 'S') != 0) /* Reject the special case for `set'. The real `sethi' will match. */ continue; if (insn.rs1 != insn.rd && index (opcode->args, 'r') != 0) /* Can't do simple format if source and dest are different. */ continue; fputs (opcode->name, stream); { register const char *s; if (opcode->args[0] != ',') fputs (" ", stream); for (s = opcode->args; *s != '\0'; ++s) { while (*s == ',') { fputs (",", stream); ++s; switch (*s) { case 'a': fputs ("a", stream); ++s; continue; #ifndef NO_V9 case 'N': fputs("pn", stream); ++s; continue; case 'T': fputs("pt", stream); ++s; continue; #endif /* NO_V9 */ default: break; } /* switch on arg */ } /* while there are comma started args */ fputs (" ", stream); switch (*s) { case '+': found_plus = 1; /* note fall-through */ default: fprintf (stream, "%c", *s); break; case '#': fputs ("0", stream); break; #define reg(n) fprintf (stream, "%%%s", reg_names[n]) case '1': case 'r': reg (insn.rs1); break; case '2': reg (insn.rs2); break; case 'd': reg (insn.rd); break; #undef reg #define freg(n) fprintf (stream, "%%%s", freg_names[n]) case 'e': freg (insn.rs1); break; case 'f': freg (insn.rs2); break; case 'g': freg (insn.rd); break; #undef freg #define creg(n) fprintf (stream, "%%c%u", (unsigned int) (n)) case 'b': creg (insn.rs1); break; case 'c': creg (insn.rs2); break; case 'D': creg (insn.rd); break; #undef creg case 'h': fprintf (stream, "%%hi(%#x)", (unsigned int) insn.imm22 << 10); break; case 'i': { /* We cannot trust the compiler to sign-extend when extracting the bitfield, hence the shifts. */ int imm = ((int) insn.imm13 << 19) >> 19; /* Check to see whether we have a 1+i, and take note of that fact. Note: because of the way we sort the table, we will be matching 1+i rather than i+1, so it is OK to assume that i is after +, not before it. */ if (found_plus) imm_added_to_rs1 = 1; if (imm <= 9) fprintf (stream, "%d", imm); else fprintf (stream, "%#x", (unsigned) imm); } break; #ifndef NO_V9 case 'k': print_address ((bfd_vma) (memaddr + (((int) insn.disp14 << 18) >> 18) * 4), stream); break; case 'K': print_address ((bfd_vma) (memaddr + (((int) insn.disp21 << 11) >> 11) * 4), stream); break; case 'Y': fputs ("%amr", stream); break; #endif /* NO_V9 */ case 'M': fprintf(stream, "%%asr%d", insn.rs1); break; case 'm': fprintf(stream, "%%asr%d", insn.rd); break; case 'L': print_address ((bfd_vma) memaddr + insn.disp30 * 4, stream); break; case 'l': if ((insn.code >> 22) == 0) /* Special case for `unimp'. Don't try to turn it's operand into a function offset. */ fprintf (stream, "%#x", (unsigned) (((int) insn.disp22 << 10) >> 10)); else /* We cannot trust the compiler to sign-extend when extracting the bitfield, hence the shifts. */ print_address ((bfd_vma) (memaddr + (((int) insn.disp22 << 10) >> 10) * 4), stream); break; case 'A': fprintf (stream, "(%d)", (int) insn.asi); break; case 'C': fputs ("%csr", stream); break; case 'F': fputs ("%fsr", stream); break; case 'p': fputs ("%psr", stream); break; case 'q': fputs ("%fq", stream); break; case 'Q': fputs ("%cq", stream); break; case 't': fputs ("%tbr", stream); break; case 'w': fputs ("%wim", stream); break; case 'y': fputs ("%y", stream); break; } } } /* If we are adding or or'ing something to rs1, then check to see whether the previous instruction was a sethi to the same register as in the sethi. If so, attempt to print the result of the add or or (in this context add and or do the same thing) and its symbolic value. */ if (imm_added_to_rs1) { union sparc_insn prev_insn; int errcode; memcpy(&prev_insn, buffer -4, sizeof (prev_insn)); if (errcode == 0) { /* If it is a delayed branch, we need to look at the instruction before the delayed branch. This handles sequences such as sethi %o1, %hi(_foo), %o1 call _printf or %o1, %lo(_foo), %o1 */ if (is_delayed_branch (prev_insn)) memcpy(&prev_insn, buffer - 8, sizeof(prev_insn)); } /* If there was a problem reading memory, then assume the previous instruction was not sethi. */ if (errcode == 0) { /* Is it sethi to the same register? */ if ((prev_insn.code & 0xc1c00000) == 0x01000000 && prev_insn.rd == insn.rs1) { fprintf (stream, "\t! "); /* We cannot trust the compiler to sign-extend when extracting the bitfield, hence the shifts. */ print_address (((int) prev_insn.imm22 << 10) | (insn.imm13 << 19) >> 19, stream); } } } return sizeof (insn); } } fprintf (stream, "%#8x", insn.code); return sizeof (insn); } /* Compare opcodes A and B. */ static int compare_opcodes (a, b) char *a, *b; { struct sparc_opcode *op0 = (struct sparc_opcode *) a; struct sparc_opcode *op1 = (struct sparc_opcode *) b; unsigned long int match0 = op0->match, match1 = op1->match; unsigned long int lose0 = op0->lose, lose1 = op1->lose; register unsigned int i; /* If a bit is set in both match and lose, there is something wrong with the opcode table. */ if (match0 & lose0) { fprintf (stderr, "Internal error: bad sparc-opcode.h: \"%s\", %#.8lx, %#.8lx\n", op0->name, match0, lose0); op0->lose &= ~op0->match; lose0 = op0->lose; } if (match1 & lose1) { fprintf (stderr, "Internal error: bad sparc-opcode.h: \"%s\", %#.8lx, %#.8lx\n", op1->name, match1, lose1); op1->lose &= ~op1->match; lose1 = op1->lose; } /* Because the bits that are variable in one opcode are constant in another, it is important to order the opcodes in the right order. */ for (i = 0; i < 32; ++i) { unsigned long int x = 1 << i; int x0 = (match0 & x) != 0; int x1 = (match1 & x) != 0; if (x0 != x1) return x1 - x0; } for (i = 0; i < 32; ++i) { unsigned long int x = 1 << i; int x0 = (lose0 & x) != 0; int x1 = (lose1 & x) != 0; if (x0 != x1) return x1 - x0; } /* They are functionally equal. So as long as the opcode table is valid, we can put whichever one first we want, on aesthetic grounds. */ { int length_diff = strlen (op0->args) - strlen (op1->args); if (length_diff != 0) /* Put the one with fewer arguments first. */ return length_diff; } /* Put 1+i before i+1. */ { char *p0 = (char *) index(op0->args, '+'); char *p1 = (char *) index(op1->args, '+'); if (p0 && p1) { /* There is a plus in both operands. Note that a plus sign cannot be the first character in args, so the following [-1]'s are valid. */ if (p0[-1] == 'i' && p1[1] == 'i') /* op0 is i+1 and op1 is 1+i, so op1 goes first. */ return 1; if (p0[1] == 'i' && p1[-1] == 'i') /* op0 is 1+i and op1 is i+1, so op0 goes first. */ return -1; } } /* They are, as far as we can tell, identical. Since qsort may have rearranged the table partially, there is no way to tell which one was first in the opcode table as written, so just say there are equal. */ return 0; }